Answer:
A
Step-by-step explanation:
For the expression [tex]\frac{125-8x^3}{25+10x+4x^2}[/tex], simplify the expression by factoring the numerator and denominator if possible.
[tex]\frac{125-8x^3}{25+10x+4x^2} = \frac{(5-2x)(25+10x+4x^2)}{25+10x+4x^2}[/tex]
After factoring the difference cubes, you can divide [tex]25+10x+4x^2[/tex] by itself into 1 leaving 5-2x. This can also be written as -2x+5.
