The given function is [tex]f(x) = \frac{6x-7}{11x+8} [/tex]
The degree of the polynomial of the numerator and denominator are the same (the term [tex]6x[/tex] and [tex]11x[/tex] both are to the power of 1)
So, the horizontal asymptote is obtained by dividing the constant of highest degree polynomial = [tex] \frac{6}{11} [/tex]
Answer: [tex] \frac{6}{11} [/tex]
