Answer:
- [tex]\bf{\frac{1}{2(3m-1)} }[/tex]
Step-by-step explanation:
[tex]\bf{\frac{3m}{9m^2-1} -\frac{1}{2(3m+1)}= }[/tex]
[tex]\bf{^{2)}\frac{3m}{(3m+1)(3m-1)}-^{3m-1)}\frac{1}{2(3m+1)}= }[/tex]
[tex]\bf{\frac{6m-3m+1}{2(3m+1)(3m-1)} =}[/tex]
[tex]\bf{\frac{3m+1}{2(3m+1)(3m-1)}=\frac{1}{2(3m-1)} }[/tex]
