0.0329 grams of aluminum can form by passing 353 c through an electrolytic cell containing a molten aluminum salt
AL^3+ + 3A^- = AL
3 moles of e- = 1 mole AL
3 faraday e- = 1 mole AL
3 * 96485 c = 1 mole AL
1 c = (1 / 3*96485)*27 g
353c = 353*27 / 3*96485 g
= 0.0329 g of AL
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