Given the equation :
[tex]h(t)=2(t+5)^2+4[/tex]We need to find the value of h(-8)
So, substitute with t = -8 at the given equation :
[tex]\begin{gathered} h(-8)=2(-8+5)^2+4 \\ h(-8)=2(-3)^2+4 \\ h(-8)=2\cdot9+4 \\ h(-8)=18+4 \\ \\ h(-8)=22 \end{gathered}[/tex]So, the answer is : the value of h(-8) = 22
