So we have the point A=(5,7) and the following transformation:
[tex](x,y)\rightarrow(x-5,-y+2)[/tex]
Transformations take a point as input and return another point that usually is different than the one used as input. Since our input is (5,7) then we just need to replace 5 and 7 in place of x and y on the transformation:
[tex]\begin{gathered} A^{\prime}=(x-5,-y+2)=(5-5,-7+2)=(0,-5) \\ A^{\prime}=(0,-5) \end{gathered}[/tex]
Then, the point we are looking for is A'=(0,-5).
