given angels are x+58 and x+128.
The sum of the angles in the straight line is 180 degree.
thus,
[tex]\begin{gathered} x+58+x+128=180 \\ 2x+186=180 \\ 2x=180-186 \\ 2x=-6 \\ x=-\frac{6}{2} \\ x=-3 \end{gathered}[/tex]
subsitute x =-3 in the equations,
[tex]\begin{gathered} =x+58 \\ =-3+58 \\ =55^{\circ} \end{gathered}[/tex]
Also,
[tex]\begin{gathered} =x+128 \\ =-3+128 \\ =125^{\circ} \end{gathered}[/tex]
thus, the angles are 55 and 125 degrees.
