Answer:
f(x) = x² + 5x - 66
Explanation:
The zeros of the quadratic equation are -11 and 6
Thsi means that:
x + 11 = 0
x - 6 = 0
The function will therefore be found as:
f(x) = (x + 11)(x - 6)
Expanding the function above
f(x) = x² - 6x + 11x - 66
f(x) = x² + 5x - 66
Therefore, the quadratic function that is in standard form and has zeros -11 and 6 is:
f(x) = x² + 5x - 66
