Given that the pressure in the whole process is constant, we could use the Charles's law:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Let's replace our values and solve the equation for T2:
[tex]\frac{623mL}{137C}=\frac{914mL}{T_2}\to T_2=\frac{137C\cdot914mL}{623mL}=201C[/tex]
The temperature of the gas sample will be 201°C.
