Explanation:
Step 1 - We need to rewrite the equation here:
4NH3+5O2 --> 4NO+6H2O
The ratio between ammonia (NH3) and the products are:
NH3 and NO:
4:4
NH3 and H2O:
6 H2O
So if we have 1.2 moles of ammonia:
1.2 moles of NH3 ---- x moles of NO
4 moles of NH3 ---- 4 moles of NO
x = 1.2 moles of NO
1.2 moles of NH3 --- x moles of H2O
4 moles of NH3 --- 6 moles of H2O
4x = 7.2
x = 7.2/4
x = 1.8 moles of H2O.
Answer: The total number of moles of products formed is 1.2 moles of NO and 1.8 moles of H2O.
