Given the initial coordinate: (3,2)
Moving down 1 unit means a negative displacement of 1 unit to the y-axis.
Moving left 3 units means a negative displacement of 3 units to the x-axis.
We get,
[tex](x^{\prime},y^{\prime})\text{ = (x + A,y + B) = (3 - 3, 2 - 1) = (0, 1)}[/tex]Therefore, after moving down 1 unit and left 3 units, you end at coordinate 0,1.
