We have the next polynomial function
[tex]P(x)=x^3-x^2+2[/tex]
In order to find the zero we punt the function equal to zero
[tex]x^3-x^2+2=0[/tex]
We have a given zero that is 1-i
x=1-i
than means that we need the conjugate of the zero given is also a zero
x=1+i
and then we need a third zero because the polynomial has third-degree it can be calculated if we factorize the polynomial given
[tex]\mleft(x-1-i\mright)\mleft(x-1+i\mright)\mleft(x+1\mright)=0[/tex]
Therefore the zeros are
x=-1
x=1-i
x=1+i
