1) Given data:
Area of square = 100 cm square
[tex]A=a^2[/tex][tex]\begin{gathered} a^2=100 \\ a=10\operatorname{cm} \end{gathered}[/tex]The perimeter of square is,
[tex]\begin{gathered} P=4a \\ P=4\times10 \\ P=40\operatorname{cm} \end{gathered}[/tex]2) Given data:
Perimeter of square = 116 cm
[tex]P=4a[/tex][tex]\begin{gathered} 4a=116 \\ a=29 \end{gathered}[/tex]The area os square is,
[tex]\begin{gathered} A=a^2 \\ A=29\times29 \\ A=841\operatorname{cm}\text{ square} \end{gathered}[/tex]