Question:
Solution:
Let the following trigonometric equation:
[tex]2\sin (x)+\sqrt[]{3}=\text{ 0}[/tex]
Subtract the root of 3 from both sides of the equation:
[tex]2\sin (x)=-\sqrt[]{3}[/tex]
solve for sin(x):
[tex]\sin (x)=\text{ -}\frac{\sqrt[]{3}}{2}[/tex]
Applying the trigonometric circle on the given interval, we obtain that the correct answer is:
[tex]x\text{ = }\frac{4\pi}{3}\text{ , x = }\frac{5\pi}{3}[/tex]
