The volume of a hexagonal pyramid is given by:
[tex]V=\frac{1}{3}\cdot b\cdot h[/tex]where:
[tex]\begin{gathered} b=\frac{1}{2}(a\cdot p) \\ where\colon \\ p=24 \\ a=2\sqrt[]{3} \\ b=24\sqrt[]{3} \end{gathered}[/tex]so:
[tex]\begin{gathered} V=\frac{1}{3}(24\sqrt[]{3})(6) \\ V=83.138 \end{gathered}[/tex]
