ANSWER
[tex]\sin 32^o[/tex]EXPLANATION
We want to find the cofunction of the given function.
The cofunction of a cosine function is:
[tex]\cos (\theta)=\sin (90-\theta)[/tex]Therefore, the cofunction of cos(58) is:
[tex]\begin{gathered} \cos (58)=\sin (90-58) \\ \cos (58^o)=\sin (32^o) \end{gathered}[/tex]That is the answer.
