We need to solve the following equation:
[tex]8+2(x-3)=3x-3[/tex]First we distribute the product in the left side:
[tex]\begin{gathered} 8+2(x-3)=3x-3 \\ 8+2x-6=3x-3 \end{gathered}[/tex]Then we pass all the terms with an x to the left side and all the constant terms to right side:
[tex]\begin{gathered} 8+2x-6=3x-3 \\ 2x-3x=6-3-8 \\ -x=-5 \\ x=5 \end{gathered}[/tex]So the answer is x=5.
