Given:
The zeros of the polynomial are 4 and 3i.
Required:
To find the polynomial of the function.
Explanation:
Here
[tex]\begin{gathered} x=4 \\ x=-3i \end{gathered}[/tex][tex]\begin{gathered} x-4=0\text{ and} \\ x+3i=0 \end{gathered}[/tex]
Therefore
[tex]\begin{gathered} (x-4)(x+3i)=0 \\ \\ x^2-4x-3ix-12i=0 \\ \\ x^2-(4+3i)x-12i=0 \end{gathered}[/tex]
Final Answer:
[tex]x^2-(4+3i)x-12i=0[/tex]
