First we need to find the value of x, we can use the fact that the sum of the interior angles of a quadrilateral is 360°
[tex]6x+6x+9x+9x=360[/tex][tex]\begin{gathered} 30x=360 \\ \end{gathered}[/tex]
then we isolate the x
[tex]x=\frac{360}{30}[/tex]
[tex]x=12[/tex]
then for 9x and 6x, we substitute the value of x=12
[tex]6(12)=72[/tex][tex]9(12)=108^{}[/tex]
if x =12, therefore, the angle 6x=72° and the 9x=108°
