Given
[tex]\sin x\cos x=\frac{1}{4}[/tex]
Find
solution of the above equation
Explanation
since,
[tex]\sin x\cos x=\frac{1}{4}[/tex]
so, we can write this as,
[tex]\begin{gathered} 2\sin x\cos x=\frac{1}{2} \\ \sin2x=\frac{1}{2} \end{gathered}[/tex]
so,
[tex]\begin{gathered} 2x=\sin^{-1}(\frac{1}{2}) \\ 2x=\frac{\Pi}{6}+2n\Pi \\ x=\frac{\Pi}{12}+n\Pi \end{gathered}[/tex]
Final Answer
[tex]\frac{\Pi}{12}+n\Pi[/tex]
