First let;s fill the second row
It is given that
[tex]\begin{gathered} \angle DFE=36 \\ \angle AFE=180-36=144 \end{gathered}[/tex][tex]\angle AFB=36\text{ (VERTICALLY O}\P OSITE\text{ TO }\angle DFE)[/tex][tex]\angle BFC=90-36=54[/tex]Now let us fill the third row :-
It is given that
[tex]\angle AFE=140[/tex]So
[tex]\angle DFE=180-140=40\text{ (LINEAR PAIR)}[/tex][tex]\angle AFB=\angle DFE=40\text{ (vertically opposite angles)}[/tex][tex]\angle BFC=90-40=50\text{ }[/tex]