Data:
- m = 0.210 g
- T₀ = 19.2 °C + 273 = 292. 2 K
- T = 32.0 °C + 273 = 305 K
- Ce = 4.18 J / GK
We apply the following formula
Q = mcₑΔT
Q = mcₑ (T - T₀)
We substitute Our data in the formula and solve:
Q = 0.210 g * 4.18 J / g K (305 k - 292.2 k)
Q = 11.23 J
