Answer: [tex]4(x+2\sqrt{2})(x-2\sqrt{2})[/tex]
Step-by-step explanation:
We can first take out the common factor of 4, as both 4x² and -32 are divisible by 4.
[tex]4(x^2-8)[/tex]
From here, we can assume that x²-8 is a difference of two squares even though 8 is not a perfect square.
For review, a difference of two squares [tex]a^2-b^2[/tex] can be factored into [tex](a+b)(a-b)[/tex].
[tex]4(x^2-8)\\4(x+\sqrt{8})(x-\sqrt{8})\\4(x+2\sqrt{2})(x-2\sqrt{2})[/tex]
