Equation of a Circle
Circular equations are typically organized like this:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
- [tex](h,k)[/tex] is the center of the circle
- [tex]r[/tex] is the radius of the circle
Solving the Question
We're given:
- The center is (-5,1)
- The radius is [tex]\sqrt{14}[/tex]
Plug the given information into the formula:
[tex](x-h)^2+(y-k)^2=r^2\\(x-(-5))^2+(y-1)^2=(\sqrt{14})^2\\(x+5)^2+(y-1)^2=14[/tex]
Answer
[tex](x+5)^2+(y-1)^2=14[/tex]
