Answer:
30
Step-by-step explanation:
Because EF and BC are parallel, ΔEFD, and ΔBCD are similar. Because we know what CF and DF are, we can add their lengths together to get CD, which in this case is 44 units long. Then, we can divide the length of CD and DF to get the scale of ΔEFD, which is 6/11. Because ΔEFD and ΔBCD are similar, we can multiply the length of BD by 6/11 to get the length of ED, which turns out to be 30.
