Answer:
[tex]f^{-1}(x)=\sqrt[3]{x}-1[/tex]
Step-by-step explanation:
[tex]f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1[/tex]
Graphing both inverses, they will be symmetrical about the line [tex]y=x[/tex].
