There are 237. 5 g of Sulfur,S in 475 g of SO2?
Calculation of grams of Sulfur
From the question, we can say that
- The molar mass of sulfur = 32 g/mol
- The molar mass of oxygen = 16 g/mol
Therefore,
The molar mass for SO2 = 32 + (16 × 2) g/mol = 64 g/mol
Now,
If 1 mole of SO2 contains 1 mole of S
Then 64 g of SO2, will contain 32g of S;
Such that
475 g of SO2 will give { [tex]\frac{ 32g of S) ( 475 g of SO2)}{64 of SO2}[/tex] } = 237. 5 g of Sulfur.
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