Answer:
Step-by-step explanation:
If the equations are true, they can be solved simultaneously.
Consider 2x-10y=-1 as Eq1 and 5x+6y=4 as Eq2
Multiplying Eq1 with 3 and Eq2 with 5 we get,
6x-30y=-3 -- Eq3 and 25x+30y=20 -- Eq4
Adding Eq3 and Eq4,
31x=17 Therefore, x=17/31
Plugin x=17/31 in Eq3,
6(17/31)-30y=-3 --- y=13/62
Plug In values of x and y in 7x-4y we get,
7(17/31)-4(13/62) = 3
So the value of 7x-4y = 3.
