Answer:
1.6675Γ10^-16N
Explanation:
The force of gravity that the space shuttle experiences is expressed as;
g = GM/rΒ²
G is the gravitational constant
M is the mass = 1.0 x 10^5 kg
r is the altitude = 200km = 200,000m
Substitute into the formula
g = 6.67Γ10^-11 Γ 1.0Γ10^5/(2Γ10^5)Β²
g = 6.67Γ10^-6/4Γ10^10
g = 1.6675Γ10^{-6-10}
g = 1.6675Γ10^-16N
Hence the force of gravity experienced by the shuttle is 1.6675Γ10^-16N