Answer:
8.5gm O2 produced
Explanation:
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were produced?
for every 2 moles of KCl produced, 3 moles of O2 are produced
Mol weight of KCl =39+35.5=74.5gm
13.2 gm KCl = 13.2/74.5 = 0.177 moles
this will make (3/2) X 0.177 = 0.2655 moles of O2
O2 mol wt is 32 0.2655 X32 = 8.5gm O2 produced
