Answer:
[tex]{ \bf{ \frac{dy}{dx} = \frac{3 - 4x}{4y + 2} }}[/tex]
Step-by-step explanation:
[tex]{ \sf{ \frac{dy}{dx} (2 {x}^{2} + 2 {y}^{2} - 3x + 2y = 1) }} \\ \\ { \sf{4x + 4y \frac{dy}{dx} - 3 + 2 \frac{dy}{dx} = 0 }} \\ \\ { \sf{ 4y\frac{dy}{dx} + 2 \frac{dy}{dx} = 3 - 4x }} \\ \\ { \sf{ \frac{dy}{dx}(4y + 2) = 3 - 4x }} \\ \\ { \sf{ \frac{dy}{dx} = \frac{3 - 4x}{4y + 2} }}[/tex]
[tex]{ \underline{ \tt{ \blue{christ \:† \: alone }}}}[/tex]
