Hi there!
[tex]\large\boxed{\text{33 in}^2}[/tex]
Find the total area by breaking the figure into two rectangles, one trapezoid, and one triangle.
Rectangles:
A = l × w
A = 2.75 × 4 = 11 in²
Solve for the other rectangle's length by subtracting from the total:
12 - 2 - 3 - 4 = 3
A = 3 × 3 = 9 in²
Total rectangle area: 11 + 9 = 20 in²
Trapezoid:
A = 1/2(b1 + b2)h
A = 1/2(4.25 + 2.75)3 = 21/2 = 10.5 in²
Triangle:
A = 1/2(bh)
A = 1/2(2.5 · 2) = 2.5 in²
Add up all of the areas:
20 + 10.5 + 2.5 = 33 in²
