Answer:
[tex]\frac{x-2}{x-4}[/tex]
Step-by-step explanation:
Given
[tex]\frac{x^2-5x+6}{x^2-7x+12}[/tex] ← factorise numerator and denominator
= [tex]\frac{(x-2)(x-3)}{(x-4)(x-3)}[/tex] ← cancel (x - 3) on numerator/ denominator
= [tex]\frac{x-2}{x-4}[/tex]
