Answer:
30.3 g
Explanation:
At STP, 1 mol of any gas will occupy 22.4 L.
With the information above in mind, we calculate how many moles are there in 32.0 L:
- 32.0 L ÷ 22.4 L/mol = 1.43 mol
Then we calculate how many moles would there be in 16.6 L:
- 16.6 L ÷ 22.4 L/mol = 0.741 mol
The difference in moles is:
- 1.43 mol - 0.741 mol = 0.689 mol
Finally we convert 0.689 moles of CO₂ into grams, using its molar mass:
- 0.689 mol * 44 g/mol = 30.3 g
