Answer:
[tex] = \frac{({x}^{3} - 2x - 3)}{(x + 3)} \\ rationalise \: the \: denominator \\ = \frac{({x}^{3} - 2x - 3)(x - 3)}{(x + 3)(x - 3)} \\ = \frac{( {x}^{4 } - 3 {x}^{3} - {2x}^{2} + 6x - 3x + 9) }{( {x}^{2} - {3}^{2}) } \\ = \frac{( {x}^{4} - {3x}^{3} - {2x}^{2} + 3x + 9)}{( {x}^{2} - 9) } [/tex]
