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Answer:
(√6)/3
Step-by-step explanation:
The relation between cot(x) and sin(x) is ...
sin(x) = 1/√(cot(x)^2 +1)
Filling in the given value, we have ...
[tex]\displaystyle\sin{\theta}=\frac{1}{\sqrt{\left(\frac{\sqrt{2}}{2}\right)^2+1}}=\sqrt{\frac{2}{3}}\\\\\boxed{\sin{\theta}=\frac{\sqrt{6}}{3}}[/tex]
