Answer:
Given f(x) = x2 + 3x – 1, find
a) f(1)
b) f(–1)
c) f(a)
d) f(x – 1)
Step-by-step explanation:
a) f(1) = (1)2 + 3(1) – 1 = 3
b) f(–1) = (–1)2 + 3(–1) – 1 = –3
c) f(a) = a2 + 3a – 1
d) f(x – 1) = (x – 1)2 + 3(x – 1) – 1
= x2 – 2x + 1 + 3x – 3 – 1 = x2 + x –3
