Answer:
(3/2, 1, 3/2)
Step-by-step explanation:
Given the simultaneous equation
-x+y+z=1... 1
x-y+z=2 ... 2
x+y-z=1 .... 3
Add equation 1 and 2;
-x+x + y - y + z + z = 1+2
0 + 0 + 2z = 3
2z = 3
z = 3/2
Add equation 2 and 3
x+x = 2 + 1
2x = 3
x = 3/2
Substitute x = 3/2 and z = 3/2 into 3
From 3;
x+y-z = 1
3/2 + y - 3/2 = 1
y + 0 = 1
y = 1
Hence the solution (x, y, z) is (3/2, 1, 3/2)
