Hello! :)
[tex]\large\boxed{A = 32.5cm^{2}}[/tex]
We can use the following area to solve for the area of the trapezoid pictured:
[tex]A = \frac{1}{2}(b_{1} + b_{2})h[/tex]
Where:
h = height
b1 = bottom base
b2 = top base
Plug in the given values:
[tex]A = \frac{1}{2}(9 + 4)(5)[/tex]
Simplify:
[tex]A = \frac{1}{2}(65)\\\\A = 32.5 cm^{2}[/tex]
