Answer:
[tex]\huge\boxed{z=12}[/tex]
Step-by-step explanation:
[tex]\dfrac{z}{4}-2=1\qquad|\text{add 2 to both sides}\\\\\dfrac{z}{4}-2+2=1+2\\\\\dfrac{z}{4}=3\qquad|\text{multiply both sides by 4}\\\\4\!\!\!\!\diagup\cdot\dfrac{z}{4\!\!\!\!\diagup}=4\cdot3\\\\z=12[/tex]
