Answer:
Explanation:
29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .
moles contained in nitric acid solution
= .0294 x .187 moles
= 5.5 x 10ā»Ā³ moles
This must have been reacted with same amount of moles of base
moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10ā»Ā³ moles
molarity of base solution = 5.5 x 10ā»Ā³ / 22.7 x 10ā»Ā³
= .24 M .
