Answer:
[tex]V_{base}=10.2mL[/tex]
Explanation:
Hello.
In this case, since the neutralization of the acid requires equal number of moles of both acid and base:
[tex]n_{acid}=n_{base}[/tex]
Whereas we can express it in terms of concentrations and volumes:
[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]
Thus, we can compute the volume of sodium hydroxide (base) as follows:
[tex]V_{base}=\frac{M_{acid}V_{acid}}{M_{base}} \\\\V_{base}=\frac{87.0mL*0.234M}{2.00M}\\ \\V_{base}=10.2mL[/tex]
Best regards.
