Answer:
[tex]x^3+3x^2-6x-8[/tex]
Step-by-step explanation:
Unfortunately due to your very vague "question", I do not know for sure if -1, -4, and 2 are X values. But assuming they are...
Just like with quadratics, you can foil to easily identify the X value. But this time we are reversing it, and instead of 2 now we have 3.
To set up your polynomial, it should look something like this:
[tex](x+1)(x+4)(x-2)[/tex]
Now you can FOIL it if it requires you, which I have done for you.
[tex]x^3+3x^2-6x-8[/tex]
