Answer:
( 6,6) is outside
Step-by-step explanation:
(x - 2)^2 + (y - 1)^2 = 25
This is of the form
(x - h)^2 + (y - k)^2 = r^2
where ( h,k) is the center and r is the radius
(x - 2)^2 + (y - 1)^2 = 5^2
The center is at ( 2,1) and the radius is 5
P(0,5), Q(2,2) R(5,-2), and S(6,6)
Adding the radius to the y coordinate gives us 6 so the only point with a y coordinate on the circle is ( 2,6)
( 6,6) is outside the circle
