Dimajago Dimajago

03-07-2020
Mathematics

contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

09pqr4sT 09pqr4sT

03-07-2020

Answer:

0

Step-by-step explanation:

The five smallest prime numbers are 2, 3, 5, 7 and 11.

2 × 3 × 5 × 7 × 11

= 2310

Divide by 42.

2310/42

= 55, Remainder 0

Answer Link

Otras preguntas

frank had a 1.5kg bag of potting soil. he used 420g of soil to pot a plant. how many kilograms of soil are left in a bag?

1) Jonah and three of his friends are splitting the dinner bill equally among themselves. Their total bill came to $86 before tax. If they want to leave an 18%

Deon throws a ball into the air. The height, h, of the ball, in meters, at the time t seconds is modeled by the function h(t) = -5t + t + 4. 1. When will the b

In the relationship between number of towers and number of customers proportional? Explain

What would this equation be of a line into slope-intercept form, simplifying all fractions 9x+12y=-108

when are we ever going to use fractions in our lives like this is dume

9x-12=5x-4 pls help

The slope of the line whose equation is 2x + 5y + 1 = 0 is0-2750-1/5O5/2

Find the values of x and y in the diagram below. (4x-7) 86° (7y-1)⁰ (9x + 4)

Luis goes 4 laps every day to the athletics track and the track measures 800 meters how many km he runs in five days.