Answer:
B
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] = [tex]a^{\frac{1}{2} }[/tex]
Thus
([tex]\sqrt{a}[/tex] )² = [tex]a^{\frac{1}{2} }[/tex] × [tex]a^{\frac{1}{2} }[/tex] = [tex]a^{(\frac{1}{2}+\frac{1}{2}) }[/tex] = [tex]a^{1}[/tex] = a → B
