Answer:
4. (x+3)^2 =16
Step-by-step explanation:
Rewrite x^2 +6x -7 = 0 in quadratic form by compliting the square
x^2 +6x = 7 divide 6 by 2 ans square so 6/2 = 3, [tex]3^{2} = 9[/tex] add 9 on each side
x^2 +6x +9 = 7+9 =16 remember that [tex](a + b)^{2} = a^{2} +2ab + b^{2}[/tex]
[tex](x +3)^{2} = 16[/tex]
