Answer:
Step-by-step explanation:
Given the expression cos[arccsc((2√3)/3)]
let y = arccsc((2√3)/3)
Taking cosec of both sides we have;
cosecy = cosec[arccsc((2√3)/3)]
cosecy = (2√3)/3
1/siny = (2√3)/3
sin y = 3/2√3
Rationalizing 3/2√3
= 3/2√3 *√3/√3
= 3√3/2*3
= 3√3/6
= √3/2
siny = √3/2
y = arcsin(√3/2)
y = 60°
Since y = arccsc((2√3)/3) = 60°
cos[ arccsc((2√3)/3)] = cos60°
cos60° = 1/2
