Answer:
The amount of space oxygen would occupy at STP is 739.66 m³
Explanation:
Here we have STP, which stands for standard temperature and pressure
Standard temperature = 273.15 K
Standard pressure = 1 atm
From the universal gas equation, we have PV = nRT
V = n·R·T/P
R = 8.20573 m³·atm/(mol·K)
n = 0.33 moles
Therefore, V = 0.33 × 8.20573 × 273.15/1 = 739.66 m³
Therefore, the amount of space oxygen would occupy at STP = 739.66 m³.
