Answer:
(4n^2)/(21n +3) . . . . n ≠ -3/2 or 0 or 1/7
Step-by-step explanation:
[tex]\dfrac{\left(\dfrac{14n^2+19n-3}{30n^2+45n}\right)}{\left(\dfrac{49n^2-1}{20n^3}\right)}=\dfrac{(2n+3)(7n-1)}{15n(2n+3)}\cdot\dfrac{20n^3}{(7n-1)(7n+1)}\\\\=\dfrac{20n^2}{15(7n+1)}=\boxed{\dfrac{4n^2}{21n+3}}[/tex]
